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heathhoyes
Posted : Sunday, July 29, 2012 11:16:41 AM
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Joined: 4/25/2012
Posts: 10

I am trying to write a PCF

max high of the stochastics over the last 15 days > 80 and lowest of stochs over 25 days > 35

I have tried

maxh15(stoc12.3) > 80 and minl25(stoc12.3)

This is not working.

Can you please help?

Thank you

 

heathhoyes
Posted : Sunday, July 29, 2012 11:19:08 AM
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Joined: 4/25/2012
Posts: 10

Sorry here is what I tried.

maxh15(stoc12.3) > 80

and

minl25(stoc12.3) > 35

Bruce_L
Posted : Monday, July 30, 2012 9:26:28 AM


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Joined: 10/7/2004
Posts: 65,138

Assuming you are interested in the Simple Stochastic 12,3 %K, you could try the following:

MAX(STOC12.3,15) > 80 AND MIN(STOC12.3,15) > 35

PCF Formula Descriptions
Understanding Stochastics
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-Bruce
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heathhoyes
Posted : Monday, July 30, 2012 1:21:58 PM
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Joined: 4/25/2012
Posts: 10

Bruce,

Thank you!!!!  That makes sense.

have a good one,

heath

 

 

heathhoyes
Posted : Monday, July 30, 2012 3:38:33 PM
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Joined: 4/25/2012
Posts: 10

Bruce,

Is there a way to put THEN in a formula?

Such as Stoc higher than 90, then a min of 80% of the 90 stoc, then a stoc above 90?

 

MAX(STOC12.3,15) > 90  THEN 

MIN(STOC12.3,15) > (max high stoc*.80)  THEN 

MAX(STOC12.3,15) > 90

 

 

Thank you

Heath

Bruce_L
Posted : Monday, July 30, 2012 4:15:29 PM


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Joined: 10/7/2004
Posts: 65,138

In general, no. You cannot create sequences of Conditions of unknown length in a specific order.

You could check for highest Stochastic of the first five bars being above 90, the lowest Stochastic of the next five bars being above 80% of the highest Stochastic of the first five bars and the highest Stochastic of the last five bars being above 90:

MAX(STOC12.3.10,5) > 90 AND MIN(STOC12.3.5,5) > .8 * MAX(STOC12.3.10,5) AND MAX(STOC12.3,5) > 90



-Bruce
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heathhoyes
Posted : Monday, July 30, 2012 4:37:01 PM
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Joined: 4/25/2012
Posts: 10

Bruce,

Great, I'll try that.

Thanks again.

Heath

 

Bruce_L
Posted : Monday, July 30, 2012 4:38:43 PM


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Joined: 10/7/2004
Posts: 65,138

You're welcome.



-Bruce
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