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goodnfast
Posted : Tuesday, April 17, 2012 11:39:24 PM
Registered User
Joined: 3/28/2010
Posts: 7

Hi, I want to have a pcf for v12.1, or pcfs, which gives me a hammer candle result. I pulled this from researching earlier posts, and apologise if I missed your earlier answer(s) to this; I'm sure I'm not the first to ask. Here's what I copied:

- lower shadow more than twice the size of the body.
- upper shadow less than half the size of the body.

O - L > 2 * ABS(C - O) AND C - L > 2 * ABS(C - O) AND (H - O < ABS(C - O) / 2 OR H - C < ABS(C - O) / 2)
 

I'd like to add to it that this result occurs after a downtrend. How do we scan for only those that the previous 3 day candles were lower highs? That is, the high 2 days ago was lower than the high 3 days ago, and the high 1 day ago was less than the high 2 days ago, and the high today was less than the high 1 day ago?

Secondly, is it possible to use pivot points? 3 times ago the pivot point was higher than pivot point 2 times ago and pivot point 1 time ago was less than pivot point 2 times ago?

In either case, the hammer candle formula copied above would I assume follow the pcf(s) to determine the trend direction, either by lower highs or lower pivot points.

Thanks in advance for your time and help. If I may, I'm relatively new to Worden and am not certain how I'll know when you've replied, nor am I sure I can find your response. If you can send me TCmail or email it would be greatly appreciated. (email removed by moderator)

Ross
 

Bruce_L
Posted : Wednesday, April 18, 2012 9:01:19 AM


Worden Trainer

Joined: 10/7/2004
Posts: 65,138

You could check for High to be down 3-bars in a row by adding:

AND H < H1 AND H1 < H2 AND H2 < H3

To the end:

O - L > 2 * ABS(C - O) AND C - L > 2 * ABS(C - O) AND (H - O < ABS(C - O) / 2 OR H - C < ABS(C - O) / 2) AND H < H1 AND H1 < H2 AND H2 < H3

You you could check for the Pivot Point to have been down 3-bars in a row by adding:

AND H2 + L2 + C2 > H3 + L3 + C3 AND H3 + L3 + C3 < H4 + L4 + C4

To the end:

O - L > 2 * ABS(C - O) AND C - L > 2 * ABS(C - O) AND (H - O < ABS(C - O) / 2 OR H - C < ABS(C - O) / 2) AND H1 + L1 + C1 < H2 + L2 + C2 AND H2 + L2 + C2 > H3 + L3 + C3 AND H3 + L3 + C3 < H4 + L4 + C4

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