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Gold Customer
Joined: 3/22/2005 Posts: 17
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I am trying to develope some candlestick scans and RANGE is something I am unfamiliar with. I have 3 requests that once I understand, I can develope some scans. I am defining the body of the candle as the value from the Low to the High (same value would be from the High to the low...since it is the distance between those 2 prices that is important to me)
1. Range of the Open to the Close of Today is <= the Range of the Open to the Close of Yesterday.
2. Range of the body of todays candle (Open to the Close of Today) is <= 25% of the range of the entire candle (High to the Low of today).
3. Range of the body of today's candle (Open to the Close of Today) is in the lower .30% of the entire range of the day (L to the H... H to the L)
Thanks so much for any assistance that can be offered.
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Worden Trainer
Joined: 10/1/2004 Posts: 18,819
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I have all the candlestick PCFs here for you: Boolean PCFs for Candlestick Patterns
Range of the Open to the Close of Today is <= the Range of the Open to the Close of Yesterday
ABS(C-O)>ABS(C1-O1)
Range of the body of todays candle (Open to the Close of Today) is <= 25% of the range of the entire candle (High to the Low of today).
ABS(C-O)<=(H-L)*0.25
Range of the body of today's candle (Open to the Close of Today) is in the lower .30% of the entire range of the day (L to the H... H to the L)
Do you mean the highest part of today's body is at or below 30% of todays H to L range?
- Craig Here to Help!
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Gold Customer
Joined: 3/22/2005 Posts: 17
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Yes Craig...that is what I meant. Thanks
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Worden Trainer
Joined: 10/1/2004 Posts: 18,819
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Don't forget to check the link I gave, no reason to create PCFs if I've already have them for you.
Range of the body of today's candle (Open to the Close of Today) is in the lower .30% of the entire range of the day (L to the H... H to the L)
(ABS(C>O)*C)+(ABS(C<=O)*O)-L<(H-L)*0.30
- Craig Here to Help!
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