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Avoiding divide by 0 Rate this Topic:
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interrobang
Posted : Wednesday, July 13, 2005 12:12:46 PM
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Joined: 3/7/2005
Posts: 23
Greetings!

I saw the following PCF in another thread:

100/(1+((H+L+C>H1+L1+C1)*(H+L+C)*V +(H1+L1+C1>H2+L2+C2)*(H1+L1+C1)*V1 +(H2+L2+C2>H3+L3+C3)*(H2+L2+C2)*V2 +(H3+L3+C3>H4+L4+C4)*(H3+L3+C3)*V3 +(H4+L4+C4>H5+L5+C5)*(H4+L4+C4)*V4 +(H5+L5+C5>H6+L6+C6)*(H5+L5+C5)*V5 +(H6+L6+C6>H7+L7+C7)*(H6+L6+C6)*V6 +(H7+L7+C7>H8+L8+C8)*(H7+L7+C7)*V7 +(H8+L8+C8>H9+L9+C9)*(H8+L8+C8)*V8 +(H9+L9+C9>H10+L10+C10)*(H9+L9+C9)*V9)/((H+L+C<H1+L1+C1)*(H+L+C)*V +(H1+L1+C1<H2+L2+C2)*(H1+L1+C1)*V1 +(H2+L2+C2<H3+L3+C3)*(H2+L2+C2)*V2 +(H3+L3+C3<H4+L4+C4)*(H3+L3+C3)*V3 +(H4+L4+C4<H5+L5+C5)*(H4+L4+C4)*V4 +(H5+L5+C5<H6+L6+C6)*(H5+L5+C5)*V5 +(H6+L6+C6<H7+L7+C7)*(H6+L6+C6)*V6 +(H7+L7+C7<H8+L8+C8)*(H7+L7+C7)*V7 +(H8+L8+C8<H9+L9+C9)*(H8+L8+C8)*V8 +(H9+L9+C9<H10+L10+C10)*(H9+L9+C9)*V9+.00001))

I understand that the .00001 is added to avoid the possibility of dividing by zero. But in a function that has a continuous range of possible values that includes both 0 and -0.00001, isn't it just as likely that the function's value will be -0.00001 as it is to be exactly zero? Is there some generic way, perhaps using the SGN() function, to ensure that division by zero cannot possibly happen?

Rob Richardson
Bruce_L
Posted : Wednesday, July 13, 2005 12:28:21 PM


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Joined: 10/7/2004
Posts: 65,138
There are several ways this could be done. I'll think about it some more, but every generic method I've thought of so far using TeleChart would involve reproducing a significant portion (if not all) of the denominator. I'm sure other people will read this topic and think about it as well.

-Bruce
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interrobang
Posted : Wednesday, July 13, 2005 1:08:50 PM
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Joined: 3/7/2005
Posts: 23
Bruce,

Yes, I figured I'd have to reproduce the denominator. It's too bad we don't have a nice little IIF() method guaranteed to evaluate only one of its two expressions.

Rob
Bruce_L
Posted : Wednesday, July 13, 2005 2:01:46 PM


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Joined: 10/7/2004
Posts: 65,138
Here's the most straightforward method that comes to mind so far:

Replace: (denominator)
With: (denominator-(denominator=0)*.00001)

The constant is a bit arbitrary and not necessarily universal. It should be noted that while this could be useful under certain circumstances, it can add significantly to size of the formula. In addition, there probably aren't a lot of situations where it would produce significantly fewer divide by zero errors than just adding or substracting a carefully chosen constant to the denominator.

-Bruce
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bustermu
Posted : Wednesday, July 13, 2005 2:48:24 PM
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Joined: 1/1/2005
Posts: 2,645
Notice that the PCF is of the form:

100/(1+N/(D+0.00001))

where U and D are nonpositive. In view of this, It was intended that the PCF be:

100/(1+N/(D-0.00001))

in order to prevent divide by zero.

Thanks,
Jim Murphy
Bruce_L
Posted : Wednesday, July 13, 2005 2:53:58 PM


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Joined: 10/7/2004
Posts: 65,138
bustermu,
That was already changed in the original topic. I didn't think changing it in this one would make a lot of sense as it would involve editing more than the formula (although the thought crossed my mind). The conditions outlined in interrobang's hypothetical rather obviously don't apply to the formula in question anyway. Since there are strong educational advantages in pointing out the problem in the original formula, I'm glad you did.

-Bruce
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