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PCF for Avg( (Avg(AvgC2,3)-AvgC19), 5 ) Rate this Topic:
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mjtran
Posted : Tuesday, January 13, 2015 4:57:05 PM
Gold Customer Gold Customer

Joined: 2/1/2006
Posts: 98

Hello Worden trainers,

Please help me with the following equation that I am trying to accomplish:

AVG(  (Avg(AvgC2,3)-AvgC19), 5 )

I got Avg( AvgC2, 3 ) - AvgC19 the same as

(C0+2*(C1+C2)+C3)/6 - AvgC19

Then I translate it further with the next Avg( ***, 5 ), of the equation above, and got the following, but when I try to plot it out, it does not seem to be correct.

( (AvgC5.0+AvgC5.3)*0.83+(AvgC5.1+AvgC5.2)*0.6-Avg(AvgC19.0,5))

Your help is very much appreciated.

Thank you,

-mjtran

mjtran
Posted : Tuesday, January 13, 2015 6:36:32 PM
Gold Customer Gold Customer

Joined: 2/1/2006
Posts: 98

I think it came out to:

((C0+C7+3*(C1+C6)+5*(C2+C5)+6*(C3+C4))/30-Avg(AvgC19.0,5))

I wish it something much simpler than the equation above.

Please correct me if I am wrong!

 

Thank you,

-mjtran

 

Bruce_L
Posted : Wednesday, January 14, 2015 9:46:22 AM


Worden Trainer

Joined: 10/7/2004
Posts: 65,138

Your Indicator Formula should work, but the following might be a bit more intuitive.

(AVG(AVGC5,3) + AVG(AVGC5.1,3)) / 2 - AVG(AVGC19,5)



-Bruce
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