Registered User Joined: 12/28/2010 Posts: 33
|
I would like to create a condition using the momentum indicator that measures the last 3 days asking on the first day momentum is down and second day is up and the third day is down but not lower than the first day's. On a chart its like a double bottom formation before forming the fourth leg up but its formed on the momentum indicator I hope this is understandable Thanks
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
What is the period of the Momentum indicator?
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
Daily
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
I don't actually need to know the time frame, but I do need know the period to be able to create a formula for the Momentum indicator.
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
Period is 1 Sorry
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
Please try the following Condition Formula:
C2 / C3 < C3 / C4 AND C2 / C3 < C / C1 AND C / C1 < C1 / C2
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
And could you send me the inverse of this formula too day 1 momentum is up day 2 down and day 3 is up but not greater than day1 resulting in a double top Thanks
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
Just replace all ef the < signs with > signs:
C2 / C3 > C3 / C4 AND C2 / C3 > C / C1 AND C / C1 > C1 / C2
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
Ok Thanks Also I would like to add to the condition to reflect after 3 down days for the first formula you sent and after 3 up days for the second Thanks
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
Adding 3 down momentum days to the beginning of the first formula would result in:
C5 / C6 < C6 / C7 AND C4 / C5 < C5 / C6 AND C3 / C4 < C4 / C5 AND C2 / C3 < C3 / C4 AND C2 / C3 < C / C1 AND C / C1 < C1 / C2
Adding 3 up momentum days to the beginning of the second formula would result in:
C5 / C6 > C6 / C7 AND C4 / C5 > C5 / C6 AND C3 / C4 > C4 / C5 AND C2 / C3 > C3 / C4 AND C2 / C3 > C / C1 AND C / C1 > C1 / C2
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
Thanks
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
I meant 3 down days in price for the first condition and 3 up days in price for the second condition
Thanks
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
By an up day in price do you mean the current close is greater than the previous close, the current close is greater than the current open or something else?
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
3 down days = 3 consecutive lower closing prices for the first condition
3 up days = 3 consecutive higher closing prices for the second condition
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
I would like that added to the first two conditions you sent Thanks
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
Having the most recent 3-bars also have negative net changes in addition to the requirements of the first formula would result in:
C < C1 AND C1 < C2 AND C2 < C3 AND C2 / C3 < C3 / C4 AND C2 / C3 < C / C1 AND C / C1 < C1 / C2
Having the most recent 3-bars also have positive net changes in addition to the requirements of the second formula would result in:
C > C1 AND C1 > C2 AND C2 > C3 AND C2 / C3 > C3 / C4 AND C2 / C3 > C / C1 AND C / C1 > C1 / C2
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
Hey Bruce,
Could you send me the below formulas using the W%R as the indicator instead of momentum with a period of 1 Thanks
Having the most recent 3-bars also have negative net changes in addition ot the requirements of the first formula would result in:
C < C1 AND C1 < C2 AND C2 < C3 AND C2 / C3 < C3 / C4 AND C2 / C3 < C / C1 AND C / C1 < C1 / C2
Having the most recent 3-bars also have positive net changes in addition ot the requirements of the second formula would result in:
C > C1 AND C1 > C2 AND C2 > C3 AND C2 / C3 > C3 / C4 AND C2 / C3 > C / C1 AND C / C1 > C1 / C2
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
Having the most recent 3-bars have negative net changes in both price and a 1-Period Williams %R would result in:
C < C1 AND C1 < C2 AND C2 < C3 AND STOC1 < STOC1.1.1 AND STOC1.1.1 < STOC1.1.2 AND STOC1.1.2 < STOC1.1.3
Having the most recent 3-bars have positive net changes in both price and a 1-Period Williams %R would result in:
C > C1 AND C1 > C2 AND C2 > C3 AND STOC1 > STOC1.1.1 AND STOC1.1.1 > STOC1.1.2 AND STOC1.1.2 > STOC1.1.3
Understanding Stochastics
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
HEY BRUCE
I NEED TWO DIFFERENT FORMULAS FOR THE MOMENTUM INDICATOR USING A PERIOD OF ONE
THE FIRST MEASURING 3 BARS ON A CHART IN WHICH ON THE FIRST BAR PRICE MAKES A LOW, THEN GOES UP ON THE SECOND BAR AND THEN GOES DOWN MAKING A NEW LOW ON THE THIRD BAR BUT THE MOMENTUM DOES THE SAME THING EXCEPT ON THE THIRD BAR IT DOESNT MAKE A NEW LOW RESULTING IN A POSSIBLE DOUBLE BOTTOM. I WOULD NEED THE FORMULA FOR THE INVERSE OF THIS AS WELL REFLECTING A POSSIBLE DOUBLE TOP
AND THE SECOND FORMULA IS WHEN PRICE ICLOSES DOWN BUT MOMENTUM CLOSES UP AND VICE VERSA
tHANKS
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
It depends on how you define "makes a low". If it just has to have a lower low than the bar before and after it:
L < L2 AND L1 > L2 AND L2 < L3 AND C / C1 > C2 / C3 AND C1 / C2 > C2 / C3 AND C2 / C3 < C3 / C4
With the reverse being:
H > H2 AND H1 < H2 AND H2 > H3 AND C / C1 < C2 / C3 AND C1 / C2 < C2 / C3 AND C2 / C3 > C3 / C4
If you mean something else, we would need additional clarification from you.
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
price is lower than the previous then the second is higher than the previos and the third is lower than the second but the momemtum doesnt make a new low on the third
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
You can replace the lows and highs with closing values if desired.
C < C2 AND C1 > C2 AND C2 < C3 AND C / C1 > C2 / C3 AND C1 / C2 > C2 / C3 AND C2 / C3 < C3 / C4
With the reverse being:
C > C2 AND C1 < C2 AND C2 > C3 AND C / C1 < C2 / C3 AND C1 / C2 < C2 / C3 AND C2 / C3 > C3 / C4
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Registered User Joined: 12/28/2010 Posts: 33
|
AND ALSO I NEED A FORMULA ASKING WHEN PRICE ICLOSES DOWN BUT MOMENTUM CLOSES UP AND VICE VERSA
|
|
Worden Trainer
Joined: 10/7/2004 Posts: 65,138
|
Price closing down and momentum 1 closing up would be:
C < C1 AND C / C1 > C1 / C2
Price closing up and momentum 1 closing down would be:
C > C1 AND C / C1 < C1 / C2
-Bruce Personal Criteria Formulas TC2000 Support Articles
|
|
Guest-1 |