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STOCKAFELLA
Posted : Wednesday, May 15, 2013 9:21:53 AM
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I would like to create a condition using the momentum indicator that measures the last 3 days asking on the first day momentum is down and second day is up and the third day is down but not lower than the first day's. On a chart its like a double bottom formation before forming the fourth leg up but its formed on the momentum indicator  I hope this is understandable   Thanks  

 

 

 

Bruce_L
Posted : Wednesday, May 15, 2013 9:46:20 AM


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What is the period of the Momentum indicator?



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STOCKAFELLA
Posted : Wednesday, May 15, 2013 9:51:39 AM
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Daily

Bruce_L
Posted : Wednesday, May 15, 2013 9:55:28 AM


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I don't actually need to know the time frame, but I do need know the period to be able to create a formula for the Momentum indicator.



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STOCKAFELLA
Posted : Wednesday, May 15, 2013 10:02:45 AM
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Period is 1  Sorry

Bruce_L
Posted : Wednesday, May 15, 2013 10:09:08 AM


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Please try the following Condition Formula:

C2 / C3 < C3 / C4 AND C2 / C3 < C / C1 AND C / C1 < C1 / C2



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STOCKAFELLA
Posted : Wednesday, May 15, 2013 10:20:24 AM
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And could you send me the inverse of this formula too  day 1 momentum is up day 2 down and day 3 is up but not greater than day1 resulting in a double top  Thanks

Bruce_L
Posted : Wednesday, May 15, 2013 10:25:01 AM


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Just replace all ef the < signs with > signs:

C2 / C3 > C3 / C4 AND C2 / C3 > C / C1 AND C / C1 > C1 / C2



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STOCKAFELLA
Posted : Wednesday, May 15, 2013 10:31:12 AM
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Ok Thanks   Also I would like to add to the condition to reflect after 3 down days  for the first formula you sent and after 3 up days for the second  Thanks

Bruce_L
Posted : Wednesday, May 15, 2013 10:43:35 AM


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Adding 3 down momentum days to the beginning of the first formula would result in:

C5 / C6 < C6 / C7 AND C4 / C5 < C5 / C6 AND C3 / C4 < C4 / C5 AND C2 / C3 < C3 / C4 AND C2 / C3 < C / C1 AND C / C1 < C1 / C2

Adding 3 up momentum days to the beginning of the second formula would result in:

C5 / C6 > C6 / C7 AND C4 / C5 > C5 / C6 AND C3 / C4 > C4 / C5 AND C2 / C3 > C3 / C4 AND C2 / C3 > C / C1 AND C / C1 > C1 / C2



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STOCKAFELLA
Posted : Wednesday, May 15, 2013 10:44:14 AM
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Thanks

STOCKAFELLA
Posted : Wednesday, May 15, 2013 10:57:33 AM
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I meant 3 down days in price for the first condition and 3 up days in price for the second condition

 

Thanks

Bruce_L
Posted : Wednesday, May 15, 2013 11:04:35 AM


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By an up day in price do you mean the current close is greater than the previous close, the current close is greater than the current open or something else?



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STOCKAFELLA
Posted : Wednesday, May 15, 2013 11:14:23 AM
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3 down days = 3 consecutive lower closing prices for the first condition

3 up days = 3 consecutive higher closing prices for the second condition

 

STOCKAFELLA
Posted : Wednesday, May 15, 2013 11:19:23 AM
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I would like that added to the first two conditions you sent   Thanks

Bruce_L
Posted : Wednesday, May 15, 2013 11:50:39 AM


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Having the most recent 3-bars also have negative net changes in addition to the requirements of the first formula would result in:

C < C1 AND C1 < C2 AND C2 < C3 AND C2 / C3 < C3 / C4 AND C2 / C3 < C / C1 AND C / C1 < C1 / C2

Having the most recent 3-bars also have positive net changes in addition to the requirements of the second formula would result in:

C > C1 AND C1 > C2 AND C2 > C3 AND C2 / C3 > C3 / C4 AND C2 / C3 > C / C1 AND C / C1 > C1 / C2



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STOCKAFELLA
Posted : Thursday, May 23, 2013 10:54:21 AM
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Hey Bruce,

Could you send me the below formulas using the W%R as the indicator instead of momentum with a period of 1  Thanks

 

 

Having the most recent 3-bars also have negative net changes in addition ot the requirements of the first formula would result in:

C < C1 AND C1 < C2 AND C2 < C3 AND C2 / C3 < C3 / C4 AND C2 / C3 < C / C1 AND C / C1 < C1 / C2

Having the most recent 3-bars also have positive net changes in addition ot the requirements of the second formula would result in:

C > C1 AND C1 > C2 AND C2 > C3 AND C2 / C3 > C3 / C4 AND C2 / C3 > C / C1 AND C / C1 > C1 / C2

Bruce_L
Posted : Thursday, May 23, 2013 11:07:14 AM


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Having the most recent 3-bars have negative net changes in both price and a 1-Period Williams %R would result in:

C < C1 AND C1 < C2 AND C2 < C3 AND STOC1 < STOC1.1.1 AND STOC1.1.1 < STOC1.1.2 AND STOC1.1.2 < STOC1.1.3

Having the most recent 3-bars have positive net changes in both price and a 1-Period Williams %R would result in:

C > C1 AND C1 > C2 AND C2 > C3 AND STOC1 > STOC1.1.1 AND STOC1.1.1 > STOC1.1.2 AND STOC1.1.2 > STOC1.1.3

Understanding Stochastics



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STOCKAFELLA
Posted : Wednesday, June 5, 2013 9:32:04 AM
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HEY BRUCE

 

I NEED TWO DIFFERENT FORMULAS FOR THE MOMENTUM INDICATOR USING A PERIOD OF ONE

THE FIRST MEASURING 3 BARS ON A  CHART IN WHICH ON THE FIRST BAR PRICE MAKES A LOW, THEN GOES UP ON THE SECOND BAR AND THEN GOES DOWN MAKING A NEW LOW ON THE THIRD BAR BUT THE MOMENTUM DOES THE SAME THING EXCEPT ON THE THIRD BAR IT DOESNT MAKE A NEW LOW RESULTING IN A POSSIBLE DOUBLE BOTTOM. I WOULD NEED THE FORMULA FOR THE INVERSE OF THIS AS WELL REFLECTING A POSSIBLE DOUBLE TOP

 

AND THE SECOND FORMULA IS WHEN PRICE ICLOSES  DOWN BUT MOMENTUM CLOSES UP AND VICE VERSA

 

tHANKS

Bruce_L
Posted : Wednesday, June 5, 2013 9:44:11 AM


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It depends on how you define "makes a low". If it just has to have a lower low than the bar before and after it:

L < L2 AND L1 > L2 AND L2 < L3 AND C / C1 > C2 / C3 AND C1 / C2 > C2 / C3 AND C2 / C3 < C3 / C4

With the reverse being:

H > H2 AND H1 < H2 AND H2 > H3 AND C / C1 < C2 / C3 AND C1 / C2 < C2 / C3 AND C2 / C3 > C3 / C4

If you mean something else, we would need additional clarification from you.



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STOCKAFELLA
Posted : Wednesday, June 5, 2013 9:50:22 AM
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price is lower  than the previous then the second is higher than the previos and the third is lower than the second but the momemtum doesnt make a new low on the third 

Bruce_L
Posted : Wednesday, June 5, 2013 9:56:10 AM


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You can replace the lows and highs with closing values if desired.

C < C2 AND C1 > C2 AND C2 < C3 AND C / C1 > C2 / C3 AND C1 / C2 > C2 / C3 AND C2 / C3 < C3 / C4

With the reverse being:

C > C2 AND C1 < C2 AND C2 > C3 AND C / C1 < C2 / C3 AND C1 / C2 < C2 / C3 AND C2 / C3 > C3 / C4



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STOCKAFELLA
Posted : Wednesday, June 5, 2013 10:10:37 AM
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AND ALSO I NEED A FORMULA ASKING  WHEN PRICE ICLOSES  DOWN BUT MOMENTUM CLOSES UP AND VICE VERSA

 

Bruce_L
Posted : Wednesday, June 5, 2013 10:13:02 AM


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Price closing down and momentum 1 closing up would be:

C < C1 AND C / C1 > C1 / C2

Price closing up and momentum 1 closing down would be:

C > C1 AND C / C1 < C1 / C2



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