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JDiStefano
Posted : Saturday, December 30, 2006 2:01:10 PM
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Joined: 5/20/2006
Posts: 101
I have a code block that has a for next loop using i to index thru the data.. Is it possible to nest another for next loop with in it and use another variable say x to further ahead in the data? then revert back to where i was/is and continue? for instance:


For i As Integer = 1 To inputcount -1
if XYZ(i) = true then (looking for a pattern)
found = true
for x as integer = (i+3) to inputcount-1
< look ahead for price to be < the inputhigh(i).. look thru all the data for the first instance
next
end if <go back to i and look for another pattern>
next

I know this won't compile.. I am thinking conceptually.. also would it be possible to actually talk to someone regarding coding something?

Thankyou
testOP2
Posted : Saturday, December 30, 2006 5:12:46 PM

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Joined: 10/7/2004
Posts: 378
Actually at first glance I think it will compile... but may or may not give you the results you want. First off, you will miss the first index in the array because you start "for i as integer = 1" instead of 0. Also, the second loop will not enter when i+3>inputcount-1, which if thats what you want is fine. Probably a safer way to do this would be like so:

if inputcount>=3 then ' make sure we have at least 3 values
for i as integer = 2 to inputcount-1 'start the index at the 3rd position
if XYZ(i-2) = true then 'look 2nd item back which will be 0 for first time through
found = true
for x as integer = i-2 to i 'loop through 3 indexes including current - first time through this would be 0,1,2
'look for whatever you want
if ABC(x) then

endif
next
endif
next
end if

if you want more than a 3 bar span then 3's = span and 2's = span -1

Ole
JDiStefano
Posted : Saturday, December 30, 2006 7:24:42 PM
Registered User
Joined: 5/20/2006
Posts: 101
Thanks..but I guess what I am asking is can you have a for next loop indexing with "i" find a date and value then with index"x" scroll forward from that point in time( from i) and look for that same value?

and then return to the "i" for next loop and continue:

for i = 0 to inputcount -1
look for some thing and
if found ( call it buypoint)then
for x = i to inputcount -1
look for the buypoint again(only one occurance)
if found again then
addtooutput buypoint(x)
x=inputcount-1
end if
next
end if
next


something like that?
testOP2
Posted : Saturday, December 30, 2006 11:44:30 PM

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Joined: 10/7/2004
Posts: 378
Sure...that should work.

Also, rather than set x=inputcount-1 to exit the inner loop you can just use "exit for"

Ole
JDiStefano
Posted : Saturday, December 30, 2006 11:46:01 PM
Registered User
Joined: 5/20/2006
Posts: 101
OK Thanks...put that where I had x=inputcount-1?
Kuf
Posted : Sunday, December 31, 2006 10:47:41 AM


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Joined: 9/18/2004
Posts: 3,522
Yes

Ken Gilb (Kuf)
Chief Software Engineer - Worden Brothers Inc.
Try/Catch - My RealCode Blog
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