Dear Bruce,

Thanks for all help lately. I have been working on an indicator (Indicator1 in a red/green histogram format)  which is “too sensitive”. I have noticed if I have a 2^nd indicator (Indicator 2;plotted as line) . an only use in an uptrend  . I can reduce the false signal significantly. I have figured out the PCF for that

But I must confess that I am stuck after several days of trial error. Could you please help me with 3 formulas so I only catch the following three conditions.   #1: red/green shift (green > red bar) and uptrend in indicator 2;

 #2:  green/red shift (red > green bar) + uptrend in indicator 2.

For example, if a red bar is at -2 I would like only to catch a green bar that is >+2 (and reverse for the 2^nd PCF).

#3 if green bars are 3fold higher than previous green bar and the 2^nd indicator is still in an uptrend. Hope this makes sense and you can help me. ( I tried to attach an example but couldn’t figure out how).

What are the formulas for both the histgram and the line?

Formulas are quite complex and extremly rare. I prefer not to reveal them. I rather get a general formula so I can past them in my self. Would it work for you to call them X1 and X2. I have seen you make magic by shortning things done but I can't do that at the moment. Thanks

#1

X1 > 0 AND X1.1 < 0 AND ABS(X1) > ABS(X1.1) AND X2 > X2.1

#2

X1 < 0 AND X1.1 > 0 AND AND ABS(X1) > ABS(X1.1) AND X2 > X2.1

#3

X1 >= 3 * X1.1 AND X1.1 > 0 AND X2 > B2.1

X1.1 is a 1 bar ago version of X1. If the formula is long and complex, this might involve an extensive edit or rewrite of X1.

X2.2 is a 1 bar ago version of X2. If the formula is long and complex, this might involve an extensive edit or rewrite of X2. 

In the case of something like X2 > X2.1, you may be way better off creating a difference equation and checking to see if it is greater than 0 (or add together the positive components of the difference equation to the left of the > sign and add together the negative components to the right of the > sign).

Thank you for a very quick respons! I will experiment with this!! I may comeback if I get stuck again. Have great day. 

You're welcome.