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Worden Discussion Forum » Customer Training & Support » Ask a Trainer - TC2000 version 12/18 » Problem Creating a Valid CountTrue formula

Problem Creating a Valid CountTrue formula

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traderlady

Posted : Monday, March 11, 2019 11:20:30 AM

Registered User
Joined: 10/7/2004
Posts: 1,178

This morning I created the following Custom formula:

CountTrue((L1=L and H1=H),5)

It seems that this should be a valid CountTrue formula, but v19 rejects it as invalid and gives me the option of converting it to a Custom PCF % True instead which does not give me a count.

Bruce, am I doing something wrong or is this an issue in v19?

traderlady

Bruce_L

Posted : Monday, March 11, 2019 11:54:40 AM

Worden Trainer

Joined: 10/7/2004
Posts: 65,138

I actually cannot reproduce this (I have tried both entering it as an indicator formula and as a Custom PCF Indicator), but you might want to get rid of the extra parantheses to see if it help.

CountTrue(L1 = L AND H1 = H, 5)

If this does not help, then please contact technical support.

-Bruce
Personal Criteria Formulas
TC2000 Support Articles

traderlady

Posted : Monday, March 11, 2019 12:06:57 PM

Registered User
Joined: 10/7/2004
Posts: 1,178

I am please to say that eliminating the two extra parentheses makes this formula as you provided work. Thanks, Bruce.

Bruce_L

Posted : Monday, March 11, 2019 12:43:31 PM

Worden Trainer

Joined: 10/7/2004
Posts: 65,138

You're welcome.

-Bruce
Personal Criteria Formulas
TC2000 Support Articles

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