Hello.

I'm looking to build a specific 200-day count where, count true if:

-the current bar's range is at least 23% bigger than the previous bar's range
-price then went up a minimum of 33% within the subsequent (to the range criteria-event above) three bars

If possible, would the price gain be measured from the low of the initial-range bar.

Hopefully this makes sense. Thank you very much for taking a look.

"Nothing can make sense if you don't bother reading before you hit post," I said to me.
 

If possible, please measure the price gain from the low of the initial-range bar.

If you want to exclude everything but the low of the initial range bar from the percent change calculations (so calculate the percent change from only after the period where the signal initial signal has triggered).

CountTrue(MAXH3 >= 1.33 * L3 AND H3 - L3 >= 1.23 * (H4 - L4), 200)

If you want to include the close of the initial range bar in the percent change calculations (this has to have happened after the low).

CountTrue(GREATEST(MAXH3, C3) >= 1.33 * L3 AND H3 - L3 >= 1.23 * (H4 - L4), 200)

If you want to include the high of the initial range bar in the percent change calculations (there is no guarantee this happened after the low).

CountTrue(MAXH4 >= 1.33 * L3 AND H3 - L3 >= 1.23 * (H4 - L4), 200)

Note that the above allow for three bars after the initial range bar, not including the initial range bar.

Yes, these are great. Bruce, thank you for your incredible problem solving and fast help.

Bruce, circling back to this, if I want to create a signal to watch for the intial condition (the current range compared to the last range, percent difference), is this correct?

-the current bar's range is at least 23% bigger than the previous bar's range

H - L >= 1.23 * (H1 - L1)

Thank you very much for taking a look.

Yes, that is correct, but you may want to check that the current bar has range.

H - L >= 1.23 * (H1 - L1) AND H > L

Or possibly even that the previous bar has range.

H - L >= 1.23 * (H1 - L1) AND H1 > L1

Thanks, Bruce. I wouldn't have thought of that. 

Much appreciated. Thanks again.

You're welcome.