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email2norman
Posted : Wednesday, July 27, 2016 6:09:26 AM
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Thanks for that Bruce.Now the following request goes two bars into future:

Assuming the price remains static at open till the open of the second future bar; write the

(i) formula for the exponential MACDi,j at the open of the second future bar.Write the formula in terms of O and past price movement and past exponential moving averages

(ii) formula for the  simple MACDi,j at the open of the second future bar.Write the formula in terms of O and past price movement and past simple moving averages

Bruce_L
Posted : Wednesday, July 27, 2016 10:04:06 AM


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(i)

(2 * O + (i-1) * ((2 * O + (i-1) * ((2 * O + (i-1) * XAVGCi.1) / (i+1))) / (i+1))) / (i+1) - (2 * O + (j-1) * ((2 * O + (j-1) * ((2 * O + (j-1) * XAVGCj.1) / (j+1))) / (j+1))) / (j+1)

(ii)

(3 * O + (i-3) * AVGC(i-3).1) / i - (3 * O + (j-3) * AVGC(j-3).1) / j



-Bruce
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email2norman
Posted : Friday, August 12, 2016 6:11:33 AM
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Please write the following for me:

(1) a formula that will send alert when the exponential moving average XAVGCi,j reaches a fresh low within the past 52 period and the price has not reach its fresh low

(2) (1) a formula that will send alert when the exponential moving average XAVGCi,j reaches a fresh high within the past 52 period and the price has not reach its fresh high

Bruce_L
Posted : Friday, August 12, 2016 8:50:58 AM


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Note that an EMA only has one period, not two, so I am only using XAVGCi and not XAVGCi,j in the following responses.

(1)

XAVGCi < MIN(XAVGCi.1,51) AND L > MINL52

(2)

XAVGCi > MAX(XAVGCi.1,51) AND H < MAXH52



-Bruce
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email2norman
Posted : Friday, August 12, 2016 12:46:39 PM
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Thank you bruce

 

email2norman
Posted : Friday, August 12, 2016 6:36:11 PM
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please rewrite your post on Friday, August 12, 2016 8:50:58 AM at open.

Bruce_L
Posted : Wednesday, August 17, 2016 10:02:43 AM


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(1)

(2 * O + (i-1) * XAVGCi.1) / (i+1) < MIN(XAVGCi.1,51) AND O > MINL51.1

(2)

(2 * O + (i-1) * XAVGCi.1) / (i+1) > MAX(XAVGCi.1,51) AND O < MAXH51.1



-Bruce
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email2norman
Posted : Monday, August 29, 2016 10:52:40 AM
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Assuming the next three future bars (A ,B and D) open at a value equal to the current price C, write the

(i) formula for the exponential MACDi,j at the open of the third future bar D.

(ii)formula for the simple MACDi,j at the open of the third  future bar D.

 

Bruce_L
Posted : Monday, August 29, 2016 11:15:37 AM


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(i)

(2 * C + (i-1) * ((2 * C + (i-1) * ((2 * C + (i-1) * XAVGCi) / (i+1))) / (i+1))) / (i+1) - (2 * C + (j-1) * ((2 * C + (j-1) * ((2 * C + (j-1) * XAVGCj) / (j+1))) / (j+1))) / (j+1)

(ii)

(3 * C + (i-3) * AVGC(i-3)) / i - (3 * C + (j-3) * AVGC(j-3)) / j



-Bruce
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email2norman
Posted : Sunday, September 11, 2016 9:21:56 AM
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QUOTE (Bruce_L)

Note that an EMA only has one period, not two, so I am only using XAVGCi and not XAVGCi,j in the following responses.

(1)

XAVGCi < MIN(XAVGCi.1,51) AND L > MINL52

(2)

XAVGCi > MAX(XAVGCi.1,51) AND H < MAXH52

 

Please write a formua for the  highest absolute value reached by the exponential macdi,j over the past 480bars

 

Bruce_L
Posted : Monday, September 12, 2016 11:39:07 AM


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There isn't a way to write this in TC2000. We could write a pseudo formula.

MAX(ABS(XAVGCi - XAVGCj),480)

But that formula won't actually work even if you substitute in numbers for i and j.

We could use the following technique out to 32 bars, but the formulas would be way too long and slow to be practical when extended out to 480 bars.

Min Max PCFs

The best option would be to add Donchian Channels to the following Custom PCF Indicator (with numerical values substituted for i and j).

XAVGCi - XAVGCj

But even in that case, there might not be enough data to calculate the indicator (since there are only 500 bars of data in any given time frame available in TC2000 v12/v16).



-Bruce
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email2norman
Posted : Wednesday, September 14, 2016 11:42:58 AM
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what is the highest number of bars to use in the  Donchian Channels to get accurate MAX(ABS(XAVGCi - XAVGCj) ?

Bruce_L
Posted : Thursday, September 15, 2016 12:23:58 PM


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There really isn't a fixed number. Assuming j is longer than i then it would probably be something along the lines of 500 - 5 * j. That said, you might try reducing 5 to something smaller to see if it is close enough for what you need.

If you were using simple averages instead of exponential, you could probably just use 500 - j or maybe 499 - j.

The problem with the exponential moving average is that it takes a while for there to be enough data for the value of the exponential moving average to be "accurate" (with accurate being defined as being "very close" to the value that it would have with infinite history instead of finite history).



-Bruce
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email2norman
Posted : Saturday, September 17, 2016 5:22:40 PM
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Please repeat (i) and (ii) of your post on

Tuesday, June 14, 2016 1:42:41 PM    and

Wednesday, June 29, 2016 3:00:44 PM

at 1 bar ago.

Bruce_L
Posted : Wednesday, September 21, 2016 2:46:26 PM


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I'm not sure what you are asking.

Do you want the MACD at the open of the current bar if it opened at the close of the previous bar instead of the current bar?

Do you want the MACD at the open of the next future bar but if the current bar closes at the close of the previous bar and the next future bar opens at the close of the previous bar?

Something else?



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email2norman
Posted : Saturday, September 24, 2016 7:18:46 AM
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you got it right Bruce

 

email2norman
Posted : Saturday, September 24, 2016 9:05:59 AM
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In addition please write for me the value of RSI14 at open

Bruce_L
Posted : Monday, September 26, 2016 11:18:51 AM


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The following Indicator Formula for RSI14 at open assumes you mean the plain RSI without Wilder's smoothing that would be represented by RSI14 in the Personal Criteria Formula Language.

100 * ((O > C1) * (C1 - O) + (C1 > C2) * (C2 - C1) + (C2 > C3) * (C3 - C2) + (C3 > C4) * (C4 - C3) + (C4 > C5) * (C5 - C4) + (C5 > C6) * (C6 - C5) + (C6 > C7) * (C7 - C6) + (C7 > C8) * (C8 - C7) + (C8 > C9) * (C9 - C8) + (C9 > C10) * (C10 - C9) + (C10 > C11) * (C11 - C10) + (C11 > C12) * (C12 - C11) + (C12 > C13) * (C13 - C12) + (C13 > C14) * (C14 - C13)) / (ABS(O - C1) + ABS(C1 - C2) + ABS(C2 - C3) + ABS(C3 - C4) + ABS(C4 - C5) + ABS(C5 - C6) + ABS(C6 - C7) + ABS(C7 - C8) + ABS(C8 - C9) + ABS(C9 - C10) + ABS(C10 - C11) + ABS(C11 - C12) + ABS(C12 - C13) + ABS(C13 - C14) + .00001)

While the following version uses a Wilder's RSI with Wilder's smoothing.

50 * (O - XAVGC27.1) / 14 / (.071435345 * (ABS(O - C1) + 13 / 14 * (ABS(C1 - C2) + 13 / 14 * (ABS(C2 - C3) + 13 / 14 * (ABS(C3 - C4) + 13 / 14 * (ABS(C4 - C5) + 13 / 14 * (ABS(C5 - C6) + 13 / 14 * (ABS(C6 - C7) + 13 / 14 * (ABS(C7 - C8) + 13 / 14 * (ABS(C8 - C9) + 13 / 14 * (ABS(C9 - C10) + 13 / 14 * (ABS(C10 - C11) + 13 / 14 * (ABS(C11 - C12) + 13 / 14 * (ABS(C12 - C13) + 13 / 14 * (ABS(C13 - C14) + 13 / 14 * (ABS(C14 - C15) + 13 / 14 * (ABS(C15 - C16) + 13 / 14 * (ABS(C16 - C17) + 13 / 14 * (ABS(C17 - C18) + 13 / 14 * (ABS(C18 - C19) + 13 / 14 * (ABS(C19 - C20) + 13 / 14 * (ABS(C20 - C21) + 13 / 14 * (ABS(C21 - C22) + 13 / 14 * (ABS(C22 - C23) + 13 / 14 * (ABS(C23 - C24) + 13 / 14 * (ABS(C24 - C25) + 13 / 14 * (ABS(C25 - C26) + 13 / 14 * (ABS(C26 - C27) + 13 / 14 * (ABS(C27 - C28) + 13 / 14 * (ABS(C28 - C29) + 13 / 14 * (ABS(C29 - C30) + 13 / 14 * (ABS(C30 - C31) + 13 / 14 * (ABS(C31 - C32) + 13 / 14 * (ABS(C32 - C33) + 13 / 14 * (ABS(C33 - C34) + 13 / 14 * (ABS(C34 - C35) + 13 / 14 * (ABS(C35 - C36) + 13 / 14 * (ABS(C36 - C37) + 13 / 14 * (ABS(C37 - C38) + 13 / 14 * (ABS(C38 - C39) + 13 / 14 * (ABS(C39 - C40) + 13 / 14 * (ABS(C40 - C41) + 13 / 14 * (ABS(C41 - C42) + 13 / 14 * (ABS(C42 - C43) + 13 / 14 * (ABS(C43 - C44) + 13 / 14 * (ABS(C44 - C45) + 13 / 14 * (ABS(C45 - C46) + 13 / 14 * (ABS(C46 - C47) + 13 / 14 * (ABS(C47 - C48) + 13 / 14 * (ABS(C48 - C49) + 13 / 14 * (ABS(C49 - C50) + 13 / 14 * (ABS(C50 - C51) + 13 / 14 * (ABS(C51 - C52) + 13 / 14 * (ABS(C52 - C53) + 13 / 14 * (ABS(C53 - C54) + 13 / 14 * (ABS(C54 - C55) + 13 / 14 * (ABS(C55 - C56) + 13 / 14 * (ABS(C56 - C57) + 13 / 14 * (ABS(C57 - C58) + 13 / 14 * (ABS(C58 - C59) + 13 / 14 * (ABS(C59 - C60) + 13 / 14 * (ABS(C60 - C61) + 13 / 14 * (ABS(C61 - C62) + 13 / 14 * (ABS(C62 - C63) + 13 / 14 * (ABS(C63 - C64) + 13 / 14 * (ABS(C64 - C65) + 13 / 14 * (ABS(C65 - C66) + 13 / 14 * (ABS(C66 - C67) + 13 / 14 * (ABS(C67 - C68) + 13 / 14 * (ABS(C68 - C69) + 13 / 14 * (ABS(C69 - C70) + 13 / 14 * (ABS(C70 - C71) + 13 / 14 * (ABS(C71 - C72) + 13 / 14 * (ABS(C72 - C73) + 13 / 14 * (ABS(C73 - C74) + 13 / 14 * (ABS(C74 - C75) + 13 / 14 * (ABS(C75 - C76) + 13 / 14 * (ABS(C76 - C77) + 13 / 14 * (ABS(C77 - C78) + 13 / 14 * (ABS(C78 - C79) + 13 / 14 * (ABS(C79 - C80) + 13 / 14 * (ABS(C80 - C81) + 13 / 14 * (ABS(C81 - C82) + 13 / 14 * (ABS(C82 - C83) + 13 / 14 * (ABS(C83 - C84) + 13 / 14 * (ABS(C84 - C85) + 13 / 14 * (ABS(C85 - C86) + 13 / 14 * (ABS(C86 - C87) + 13 / 14 * (ABS(C87 - C88) + 13 / 14 * (ABS(C88 - C89) + 13 / 14 * (ABS(C89 - C90) + 13 / 14 * (ABS(C90 - C91) + 13 / 14 * (ABS(C91 - C92) + 13 / 14 * (ABS(C92 - C93) + 13 / 14 * (ABS(C93 - C94) + 13 / 14 * (ABS(C94 - C95) + 13 / 14 * (ABS(C95 - C96) + 13 / 14 * (ABS(C96 - C97) + 13 / 14 * (ABS(C97 - C98) + 13 / 14 * (ABS(C98 - C99) + 13 / 14 * (ABS(C99 - C100) + 13 / 14 * (ABS(C100 - C101) + 13 / 14 * (ABS(C101 - C102) + 13 / 14 * (ABS(C102 - C103) + 13 / 14 * (ABS(C103 - C104) + 13 / 14 * (ABS(C104 - C105) + 13 / 14 * (ABS(C105 - C106) + 13 / 14 * (ABS(C106 - C107) + 13 / 14 * (ABS(C107 - C108) + 13 / 14 * (ABS(C108 - C109) + 13 / 14 * (ABS(C109 - C110) + 13 / 14 * (ABS(C110 - C111) + 13 / 14 * (ABS(C111 - C112) + 13 / 14 * (ABS(C112 - C113) + 13 / 14 * (ABS(C113 - C114) + 13 / 14 * (ABS(C114 - C115) + 13 / 14 * (ABS(C115 - C116) + 13 / 14 * (ABS(C116 - C117) + 13 / 14 * (ABS(C117 - C118) + 13 / 14 * (ABS(C118 - C119) + 13 / 14 * (ABS(C119 - C120) + 13 / 14 * (ABS(C120 - C121) + 13 / 14 * (ABS(C121 - C122) + 13 / 14 * (ABS(C122 - C123) + 13 / 14 * (ABS(C123 - C124) + 13 / 14 * (ABS(C124 - C125))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))) + 50

I presented two options for the MACD in my Wednesday, September 21, 2016 2:46:26 PM ET post. These options should be entirely different. Which one is "right"?



-Bruce
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email2norman
Posted : Wednesday, September 28, 2016 11:58:05 AM
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For clarity I will write the question:

(1)Assuming the current bar open at the price C1 of the close of the previous bar ,

write the formula for the MACD at the open of the current bar in terms of C1 and past exponential moving averages.

(2)Assuming the current bar open at the price C1 of the close of the previous bar and the price remain static at C1 and the next future bar also open at C1, write the formula for the MACD at the open of the next future bar in terms of C1 and past exponential moving averages.

Bruce_L
Posted : Wednesday, September 28, 2016 12:58:27 PM


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(1)

(2 * C1 + (i-1) * XAVGCi.1) / (i+1) - (2 * C1 + (j-1) * XAVGCj.1) / (j+1)

(2)

(2 * C1 + (i-1) * (2 * C1 + (i-1) * XAVGCi.1) / (i+1)) / (i+1) - (2 * C1 + (j-1) * (2 * C1 + (j-1) * XAVGCj.1) / (j+1)) / (j+1)



-Bruce
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email2norman
Posted : Saturday, October 15, 2016 10:19:14 AM
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Refering to my post on Wednesday, September 28, 2016 11:58:05 AM, i would like you to move the question (2) one step back as follows:

(a) 2 bars ago close at C2.Assuming the price remains at C2 till the open of the previous bar  and  the open of the current bar;

write the formula for the MACD at the open of the current bar in terms of C2 and past exponential moving averages.

Bruce_L
Posted : Monday, October 17, 2016 10:25:44 AM


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If I'm understanding correctly, it should basically just the (2) formula from my Wednesday, September 28, 2016 12:58:27 PM ET post using C2 instead of C1 as the basis.

(2 * C2 + (i-1) * (2 * C2 + (i-1) * XAVGCi.2) / (i+1)) / (i+1) - (2 * C2 + (j-1) * (2 * C2+ (j-1) * XAVGCj.2) / (j+1)) / (j+1)



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email2norman
Posted : Monday, October 17, 2016 7:28:22 PM
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The "XAVGC2.1" in the formula should be "XAVGCi.2" isn`t it?

Bruce_L
Posted : Tuesday, October 18, 2016 9:04:19 AM


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You are correct. Both of the XAVGCs should have been changed from .1 to .2.



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email2norman
Posted : Monday, November 7, 2016 2:27:10 PM
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Assuming the next future bar opens at a value equal to the current price C; write the

(i) RSIi at the open of the next future bar.

(i) RSI exponential histogram RSIi,k  at the open of the next future bar.

Bruce_L
Posted : Tuesday, November 8, 2016 10:32:28 AM


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Are you interested in the plain RSI without Wilder's smoothing or the Wilder's RSI with Wilder's smoothing?



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email2norman
Posted : Tuesday, November 8, 2016 2:05:39 PM
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plain RSI

Bruce_L
Posted : Tuesday, November 8, 2016 3:14:18 PM


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This isn't going to be all that helpful from a PCF standpoint because you would need to manually expand the moving averages.

(i)

100 * AVG(ABS(C > C1) * (C - C1),i-1) / AVG(ABS(C - C1),i-1)

(ii) This assumes the histogram is RSIi minus the j period moving average of RSIi.

100 * (AVG(ABS(C > C1) * (C - C1),i-1) / AVG(ABS(C - C1),i-1) - ((AVG(ABS(C > C1) * (C - C1),i-1) / AVG(ABS(C - C1),i-1) + (j-1) * AVG(AVG(ABS(C > C1) * (C - C1),i-1) / AVG(ABS(C - C1),i-1),j-1)) / j))



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email2norman
Posted : Sunday, November 13, 2016 3:49:59 AM
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I refer to your Tuesday, November 08, 2016 3:14:18 PM

I don't know how to expand the moving averages:please explain how to expand the moving averages and give examples using RSI50 for (i) and RSI50,20 for (ii)

Bruce_L
Posted : Thursday, November 17, 2016 2:40:19 PM


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So doing the manual expansions on RSI50 and RSI50,20 is just too long and slow to be practical. The exponential Histogram would be really bad even with short periods like RSI5,2.

This had me thinking about if there is a way to do this which would be shorter, and I think so. I am pretty sure the value of RSI50 at the next open if price stays at the current close would just be:

RSI49

Which would make the exponential RSI50,20 histogram the following at the open of the next bar if price stays at the current close.

RSI49 - (2 * RSI49 + 19 * XAVG(RSI50,20)) / 21



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email2norman
Posted : Thursday, November 17, 2016 5:27:57 PM
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Thank you bruce.

 

email2norman
Posted : Sunday, November 20, 2016 4:22:17 PM
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Assuming the next two future bars (A and B) open at a value equal to the current price C, write the

(i) formula for the exponential histogram MACDi,j,k at the open of the second future bar B.

Bruce_L
Posted : Monday, November 21, 2016 11:58:19 AM


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(1 - (i - 1) / (i - k)) * (2 * C + (i - 1) * (2 * C + (i - 1) * XAVGCi) / (i + 1)) / (i + 1) + ((j - 1) / (j - k) - 1) * (2 * C + (j - 1) * (2 * C + (j - 1) * XAVGCj) / (j + 1)) / (j + 1) + ((k - 1) / (i - k) - (k - 1) / (j - k)) * (2 * C + (k - 1) * (2 * C + (k - 1) * XAVGCk) / (k + 1)) / (k + 1)



-Bruce
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email2norman
Posted : Tuesday, November 22, 2016 2:27:44 AM
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Please write the following for me.All the formulas should contain the current open price and past exponential moving averages.

(i) Formula for exponential histogram MACDi,j,k at open

(ii) Assuming the price at current open remains static till the open of the next future bar

write the formula of  exponential histogram MACDi,j,k at the open of the next future bar

(iii) Assuming the price at current open remains static till the open of the second  future bar

write the formula of  exponential histogram MACDi,j,k at the open of the second future bar

Bruce_L
Posted : Wednesday, November 23, 2016 9:36:45 AM


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QUOTE (email2norman)
(i) Formula for exponential histogram MACDi,j,k at open

(1 - (i - 1) / (i - k)) * (2 * O + (i - 1) * XAVGOi.1) / (i + 1) + ((j - 1) / (j - k) - 1) * (2 * O + (j - 1) * XAVGOj.1) / (j + 1) + ((k - 1) / (i - k) - (k - 1) / (j - k)) * (2 * O + (k - 1) * XAVGOk.1) / (k + 1)

QUOTE (email2norman)
(ii) Assuming the price at current open remains static till the open of the next future bar

write the formula of  exponential histogram MACDi,j,k at the open of the next future bar

(1 - (i - 1) / (i - k)) * (2 * O + (i - 1) * (2 * O + (i - 1) * XAVGOi.1) / (i + 1)) / (i + 1) + ((j - 1) / (j - k) - 1) * (2 * O + (j - 1) * (2 * O + (j - 1) * XAVGOj.1) / (j + 1)) / (j + 1) + ((k - 1) / (i - k) - (k - 1) / (j - k)) * (2 * O + (k - 1) * (2 * O + (k - 1) * XAVGOk.1) / (k + 1)) / (k + 1)

QUOTE (email2norman)
(iii) Assuming the price at current open remains static till the open of the second  future bar

write the formula of  exponential histogram MACDi,j,k at the open of the second future bar

(1 - (i - 1) / (i - k)) * (2 * O + (i - 1) * (2 * O + (i - 1) * (2 * O + (i - 1) * XAVGOi.1) / (i + 1)) / (i + 1)) / (i + 1) + ((j - 1) / (j - k) - 1) * (2 * O + (j - 1) * (2 * O + (j - 1) * (2 * O + (j - 1) * XAVGOj.1) / (j + 1)) / (j + 1)) / (j + 1) + ((k - 1) / (i - k) - (k - 1) / (j - k)) * (2 * O + (k - 1) * (2 * O + (k - 1) * (2 * O + (k - 1) * XAVGOk.1) / (k + 1)) / (k + 1)) / (k + 1)



-Bruce
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email2norman
Posted : Thursday, November 24, 2016 2:21:07 AM
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Please write the formula for the exponential Histogram MACDi,j,k  at

(i) one bar ago

(ii) two bar ago

(iii) three bar ago

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